Jul 28, 2011 Posted by admin on Jul 28, 2011 in Featured, Logistics, Playoffs, Schedule | 0 comments

Playoffs!?! PLAYOFFS?!? Playoffs.

The 2011 Playoffs are just around the corner and there are plenty of playoff spots still up for grabs!

Here’s a quick rundown of playoff eligibility…

Any tie counts as half a win and half a loss. So we will re-calculate the winning percentages for teams that have ties in order to determine end-of-year standing.

Division winners from each conference get the byes for the first round. The next 4 teams with the best records from each conference make the playoffs, regardless of division.

Tiebreaker System:
All division winners and playoff participants will be decided based on winning percentage. The winning percentage is decided by dividing a team’s total wins by their total games played. For example, a team that is 18-3 has a winning percentage of .857 while a team that is 20-4 has a winning percentage of .833. Therefore, the 18-3 team is the division champ.

Ties will be counted as 1/2 win and 1/2 loss. As an example, a team that is 14-6-4 is 16-8 for winning percentage purposes, while 16-6-1 is 16 1/2-6 1/2. The winning percentage of the former is .667 while the latter is .717 giving it the title.

There will be times when the winning percentages end up equal. In those instances, the tie will be broken using the following system (without exception):

Two teams:
1. Head-to-head: Who beat whom when they played each other.
2. Fewest runs allowed, head-to-head: Blues beat Reds 4-3, Reds beat Blues 10-2. Reds win by virtue of allowing 6 runs to the Blues 13.
3. Winning Percentage within the division.
4. Run differential, head-to-head: As in 2. above, Blues won by 1 run, Reds won by 8 runs Reds win.
5. Fewest runs allowed per game average: take the total runs allowed for each team, and divide that figure by the total games played. The team with the lowest average runs allowed per game wins.

Three or more teams:
1. Head-to-head: Same as above, if all teams beat each other, go to.
2. Fewest runs allowed amongst each other: Mudhens beat Reds 3-1, Reds beat Blues 4-3, and
Blues beat Mudhens 4-0. Mudhens allowed 5 runs, Reds allowed 6, and the Blues allowed 4.
Blues are the winner.
3. If these leave two or more teams, steps 3-5 above (in the two team scenario) will be performed
to determine the winner.
In computing runs allowed, forfeits are treated as 9-0 losses.

Good luck the rest of the way!!!